1890 Belgian general election
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|
69 of the 138 seats in the Chamber of Representatives 70 seats needed for a majority |
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First party
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Second party
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| Leader
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Auguste Beernaert
|
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Party
|
Catholic
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Liberal
|
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Leader since
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Candidate for PM
|
|
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Seats before
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98 seats
|
40 seats
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Seats won
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29
|
40
|
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Seats after
|
94
|
44
|
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Seat change
|
4
|
4
|
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Popular vote
|
17,253
|
20,829
|
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Percentage
|
45.15%
|
54.51%
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|
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Partial general elections were held in Belgium on 10 June 1890.[1][2] In the elections for the Chamber of Representatives the result was a victory for the Catholic Party, which won 94 of the 138 seats.[2]
Under the alternating system, elections were held in only four out of the nine provinces: Hainaut, Limburg, Liège and East Flanders. Thus, only 69 seats out of the 138 were up for election. Additionally, a special election was held in Neufchâteau on 3 June 1890 after the death of Edmond van der Linden d'Hooghvorst (d).[3] Winand Heynen (d) was elected to replace him.
Results
Chamber of Representatives
Party
|
Votes
|
%
|
Seats
|
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Won
|
Total
|
+/–
|
---|
Liberal Party |
20,829 |
54.5 |
40 |
44 |
+4
|
Catholic Party |
17,253 |
45.2 |
29 |
94 |
–4
|
Belgian Labour Party |
98 |
0.3 |
0 |
0 |
New
|
Others |
30 |
0.1 |
0 |
0 |
0
|
Invalid/blank votes |
|
– |
– |
– |
–
|
Total |
38,210 |
100 |
69 |
138 |
0
|
Registered voters/turnout |
59,452 |
|
– |
– |
–
|
Source: Mackie & Rose,[4] Sternberger et al.
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Constituencies
The distribution of seats among the electoral districts was as follows:[5]
References